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[C/C++] 快速求 sqrt 倒數的方法

float InvSqrt (float x) { float xhalf = 0.5f*x; int i = *(int*)&x; i = 0x5f3759df – (i>>1); x = *(float*)&i; x = x*(1.5f – xhalf*x*x); return x;} …

2009-08-04 pickerweng

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